0.36g of an organic compound containing sulphur produced H2SO4 by Carius method, which on treatment with BaCl2 produced quantitatively 0.2330g of BaSO4. Calculate the percentage of S in the compound..??
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0.36g of an organic compound containing sulphur produced H2SO4 by Carius method, which on treatment with BaCl2 produced quantitatively 0.2330g of BaSO4. Calculate the percentage of S in the compound..??
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Answer:
8.89%
Explanation:
Moles of S in BaSO4 = 1 * Mole of BaSO4
= 0.2330/233 = 0.001
Weight of S = 0.001 * 32 g = 0.032g
Percentage of S = 0.032/0.36 * 100 = 8.89%.
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