If sec theta = 17/8 then prove that 3-4 sin ² theta / 4 cos² theta -3 = 3-tan²theta/ 1-3 tan² theta pls answer quickly .. it's urgent
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If sec theta = 17/8 then prove that 3-4 sin ² theta / 4 cos² theta -3 = 3-tan²theta/ 1-3 tan² theta pls answer quickly .. it's urgent
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