1. A ABC and A DBC are two isosceles triangles on the same base BC and vertices A and D are on the
same side of BC (see Fig. 7.39). IfAD is extended
to intersect BC at P. show that
A ABD=AACD
(0) ААВРААСР
(ii) AP bisects Z A as well as Z D.
(iv) AP is the perpendicular bisector of BC.
B
PB
Fig. 7.391
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