1. A body of mass 1 kg is kept at rest. A constant force of 6 N starts acting on
it. Find the time taken by the body to move through a distance of 12 m.
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1. A body of mass 1 kg is kept at rest. A constant force of 6 N starts acting on
it. Find the time taken by the body to move through a distance of 12 m.
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Verified answer
Answer :-
Given :-
To Find :-
Solution :-
To find time, we first need to find acceleration and then substitute the value of given in the second equation of motion -
➩ Force = Mass × Acceleration
➩ 6 = 1 × a
➩ a = 6 m/s²
Substituting the value in 2nd equation of motion :-
➩ s = ut + 1/2 at²
➩ 12 = 0 + 1/2 × 6 × t²
➩ 12 = 3t²
➩ t² = 12/3
➩ t² = 4
➩ t = 2 sec
Time taken = 2 sec
Given :-
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To find :-
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[tex]\\[/tex]
Solution :-
[tex]\\[/tex]
[tex]\\[/tex]
[tex]\underline{\bf{\bigstar} \: \mathfrak{As \: we \: know \: that}}[/tex]
[tex]\\[/tex]
• [tex]\boxed{\bf{Force~=~Mass~×~Acceleration}}[/tex]★
[tex]\\[/tex]
[tex]\\[/tex]
[tex]\\[/tex]
★ Substituting the value,
[tex]\\[/tex]
[tex]\\[/tex]
:[tex]\implies[/tex]s = [tex]\large{\sf{ut \: + \: \frac{1}{2} \: at²}} [/tex]
[tex]\\[/tex]
[tex]~~~~~[/tex]:[tex]\implies[/tex][tex]\large{\sf{0 \: + \: \frac{1}{2} \: \times \: 6 \: \times t²}}[/tex]
[tex]\\[/tex]
[tex]~~~~~~~~~~[/tex]:[tex]\implies[/tex]12 = 3t²
[tex]\\[/tex]
[tex]~~~~~~~~~~~~~~~[/tex]:[tex]\implies[/tex]t² = [tex]\large{\sf{\frac{12}{3}}}[/tex]
[tex]\\[/tex]
[tex]~~~~~~~~~~~~~~~~~~~~[/tex]:[tex]\implies[/tex]t² = [tex]{\sf{\dfrac{\cancel{12}}{\cancel{3}}}}[/tex]
[tex]\\[/tex]
[tex]~~~~~~~~~~~~~~~~~~~~~~~~~[/tex]:[tex]\implies[/tex] [tex]\large{\underline{\boxed{\pink{\frak{t~=~2~sec}}}}}[/tex]★
[tex]\\[/tex]
[tex]\large\dag[/tex] Hence,
[tex]\\[/tex]