1. A force of 50 N acts on a body of mass 10 kg at rest. What is its acceleration? What is
its velocity after 5 seconds if the same force acts?
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1. A force of 50 N acts on a body of mass 10 kg at rest. What is its acceleration? What is
its velocity after 5 seconds if the same force acts?
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Verified answer
Given :-
→ Magnitude of force = 50 N
→ Mass of the body = 10 kg
→ Time = 5 seconds
To find :-
→ Acceleration of the body.
→ It's velocity after 5 seconds.
Solution :-
According to Newton's 2nd Law of motion, we know that :-
F = ma
⇒ 50 = 10(a)
⇒ a = 50/10
⇒ a = 5 m/s²
Hence, acceleration is 5 m/s² .
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Since, the body was at rest initially. So, it's initial velocity will be 0 m/s .
Now, by the 1st equation of motion :-
v = u + at
⇒ v = 0 + 5(5)
⇒ v = 0 + 25
⇒ v = 25 m/s
Thus, velocity of the body after 5 seconds is 25 m/s .
Verified answer
Answer:
Explanation:
Given,
Force applied on the body, F = 50 N
Mass of the body, m = 10 kg
Time, t = 5 seconds
To Find,
Acceleration, a
Final velocity, v
Formula to be used,
Newton's 2nd law, F = ma
1st equation of motion, v = u + at
Solution,
Putting all the values, we get
F = ma
⇒ 50 = 10 × a
⇒ a = 50/10
⇒ a = 5 m/s².
Hence, the acceleration is 5 m/s².
Now, the final velocity,
v = u + at
⇒ v = 0 + 5 × 5
⇒ v = 25 m/s
Hence, the final velocity is 25 m/s.