tan A/2=3/2 then, 1+cosA/1-cos A=?
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Answer:
We know that,
cosA
= 2 cos²(A/2) - 1
= 1 - 2 sin²(A/2)
Now, (1 + cosA)/(1 - cosA)
= {1 + 2 cos²(A/2)- 1}/{1 - 1 + 2 sin²(A/2)}
= cos²(A/2) / sin²(A/2)
= 1/tan²(A/2)
= 1/(3/2)²
= 1/(9/4)
= 4/9