Definite integration 0 to 2pi [ 1 / (1 + e^sinx )]
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Definite integration 0 to 2pi [ 1 / (1 + e^sinx )]
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See attachment ,answer is π .
actually , here we use definite integration concept .
if I = ∫f(x)dx and limit [a, b]
then, we can treat it I = ∫f(a +b -x)dx with same limit .