1. In the given figure (not drawn to scale), BD is a diameter of the circle with centre 0. C and
A are two points on the circle. BA and CD,
when produced, meet at E. If ZDOC = 60° and
ZABD = 23°, then find ZOBC.
A
E
B
2309
(a) 60°
(b) 30°
(c) 45°
V60°
Find
D
(d) 67°
С
(a) 9
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