1. the sum of two consecutive odd numbers is 28, then the bigger number is
2. If ABC = PQR and ABC=75°, then PQR is
3. in a class there are 40 boys and 35 girls the ratio of boys to the total number of student is
4. Product of two integers is 256.if one of them is -8 find the another
5. If (-1) is multiplied 15 times the product is
6. A farmer Sanju borrowed Rs. 60,000 from a bank at 8% per annum, for 2 years for purchasing a tractor
(i) Write the formula to find simple interest.
(ii) Find the interest Sanju has to pay to bank,
(ii) Write the formula to find amount.
(iv) What amount Sanju have to pay after the given time?
7. One had apple is accidently mixed with some good apples in a basket. As a result of which 25% of the total apples go
bad. Now the number of good apples in the basket is 30.
(i)What is the percentage of good apples in the basket now?
(ii) Find the total number of apples kept in the basket
(iii) What is the number of bad apples in the basket now?
(iv) What is the ratio of good apples to bad apples in the baskets now?
Share
Answer:
15 is the bigger number^^
Step-by-step explanation:
1. Let the smaller number be x
Let the bigger number be x+2
Therefore ATQ,
=) x+x+2 = 28
=) 2x+2 = 28
=) 2x = 28 - 2
=) 2x = 26
=) x = 26/2
=) x = 13
Therefore the smaller number is 13
The bigger number is (13 + 2)= 15
Verified answer
Answer:
1) Let the two consecutive odd numbers be (x + 1) and (x + 3)
According to the question,
x + 1 + x + 3 = 28
2x + 4 = 28
2x = 28 - 4
2x = 24
x = 24/2 = 12
Therefore, the bigger number is 15.
2) ∠PQR = 75°
Because ΔABC and ΔPQR are similar triangles.
3) Number of boys = 40
Number of girls = 35
Total number of students = number of boys + number of girls
= 40 + 35
= 75
The ratio of boys to total number of students :
= 40 : 75
= 5(8) : 5(15)
= 8 : 15
4) Product of two integers = 256
One of them = -8
Let another integer be 'a'
a × (-8) =256
-8a = 256
a = 256/-8
a = -42
Therefore, the other integer is -42.
5) (-1) is multiplied 15 times.
⇒ (-1)¹⁵
⇒ -1
6) P = Rs. 60,000
r = 8%
t = 2 years
(i) Simple Interest = P × r × t
(ii) S.I = 60,000 × 8/100 × 2
= 600 × 16
= Rs. 9600
(iii) Amount = Principal + Simple interest
(iv) Amount he has to pay = 60,000 + 9600
= Rs. 69600
7) Number of bad apples = 25% of the total apples
Number of good apples = 30
Let the total number of apples be 'a'.
(i) Percentage of good apples in the basket = (100 - 25)% = 75%
(ii) Number of good apples = 75% of total apples = 30
[tex]\rm \dfrac{75}{100}a=30 \\\\ \rm \dfrac{3a}{4}=30 \\\\ \rm a=30 \times \dfrac{4}{3} \\\\ \rm a=40[/tex]
Therefore, the total number of apples kept in the basket = 40.
(iii) Number of bad apples = 25% of total apples
= 25/100 × 40
= 10
(iv) Ratio of good apples to bad apples :
= 30 : 10
= 3 : 1