(1) Two pendulums have length 81 cm and 1.44cm . Find the ratio of their
1) Time periods
2) Frequency
(2) draw a graph of l , the lenght of simple pendulum against t2 , the square of its time period
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(1) Two pendulums have length 81 cm and 1.44cm . Find the ratio of their
1) Time periods
2) Frequency
(2) draw a graph of l , the lenght of simple pendulum against t2 , the square of its time period
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the formula of time period of a pendulum is T=√l/g...............where l is the length of the pendulum
therefore , the time period is directly propotional to the under root of length
T1/T2= √L1/L2
√81/1.44
9/1.2= 90/12
15/2
frequency is inversly propotional to the time period
n1/n2= 2/15
1)
1)7.45sec
2)0.1329 Hz