suman split a bag of chocolates amongst four children. payal got 7/15 , subha got 7/8, raj got 7/20 and lata got 7/10. arrange the name of the children in the order who got from least to greatest number of chocolates.
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suman split a bag of chocolates amongst four children. payal got 7/15 , subha got 7/8, raj got 7/20 and lata got 7/10. arrange the name of the children in the order who got from least to greatest number of chocolates.
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Answer:
Let first number be x.
According to the question second number is x + 1 and the third is x + 2
Sum of first and second numbers = (x) + (x + 1).
According to question:
⇒ (x) + (x + 1) = 15 + (x + 2)
⇒ 2x + 1 = 17 + x
Transposing x to LHS and 1 to RHS, we get
⇒2x – x = 17 – 1
⇒ x = 16
So, first number = x = 16,
Second number = x + 1 = 16 + 1 = 17
And third number = x + 2 = 16 + 2 = 18
Thus, the required consecutive natural numbers are 16, 17 and 18.
Answer:
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