100 points with explanation pls answer
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I am not using the hint to solve it.We know that any triangle inscribed in a semicircle is a right angled triangle.
Here, the diameter of the circle is the hypotenuse of the triangle.
Coming to the question, Angle B is 90°. So AC is the hypotenuse of the triangle.
If you construct a semicircle with AC as diameter, you will see that vertex B will lie on the semicircle.
Given that point O is midpoint of AC.
So OA = OC = AC/2 = radius of semicircle
Join O and B.
Since B lies in semicircle, OB is also a radius
Thus, OA = OB = OC = AC/2
(Proved)