127 Three times the trust of the there consecutive add integers is 3 more than twice the third Poteger. Find the third Integer. HOGA
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127 Three times the trust of the there consecutive add integers is 3 more than twice the third Poteger. Find the third Integer. HOGA
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Answer:
Let the three consecutive odd integers be x, x+2, x+4
Three times the first of three consecutive odd integers is 3 more than twice the third.
∴ 3x=2(x+4)+3
Hence, the third integer is 11+4=15.
Hence, This is Answer
Step-by-step explanation:
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