[tex]\colorbox{lightgreen} {\red★Ques:-}[/tex]
The mole fraction of methanol when equal masses of methanol and ethanol are mixed together is
(1) 39/23
(2) 12/17
(3) 23/39
(4) 17/12
please provide proper steps
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[tex]\colorbox{lightgreen} {\red★Ques:-}[/tex]
The mole fraction of methanol when equal masses of methanol and ethanol are mixed together is
(1) 39/23
(2) 12/17
(3) 23/39
(4) 17/12
please provide proper steps
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Answer:
[tex]\huge{\bf{{\underline{\colorbox{black} {\color{white}{➳Aɳʂɯҽɾ:-}}}}}}[/tex]
To compute the mole fraction of a component in a solution, we first need to calculate the number of moles of each substance.
The formula for moles is:
Moles = mass / molar mass
Given equal masses of Methanol and Ethanol, we need to divide by their respective molar masses to find the number of moles.
Molar mass of Methanol (CH3OH) = 32.04 g/mol
Molar mass of Ethanol (C2H5OH) = 46.07 g/mol
Let the common mass of Methanol and Ethanol be x.
Now, we can calculate the number of moles in Methanol and Ethanol as follows:
Moles of Methanol = x / 32.04
Moles of Ethanol = x / 46.07
The mole fraction of Methanol is then calculated by dividing the moles of Methanol by the total moles (moles of Methanol + moles of Ethanol)
Mole fraction of Methanol = (x / 32.04) / (x / 32.04 + x / 46.07)
Solving the above expression and simplifying, we get:
Mole fraction of Methanol = (1 / 32.04) / (1 / 32.04 + 1 / 46.07)
This simplifies to approximately 0.59 or can be expressed as 23/39, so the correct answer is (3) 23/39.