14. A wire is in the shape of a rectangle. Its length is 40 cm and breadth is 22 cm. If the
same wire is re-bent in the shape of a square, what will be the measure of each side?
Also, find which shape encloses more area?
Share
14. A wire is in the shape of a rectangle. Its length is 40 cm and breadth is 22 cm. If the
same wire is re-bent in the shape of a square, what will be the measure of each side?
Also, find which shape encloses more area?
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Step-by-step explanation:
According to the question,
Perimeter of square=Perimeter of rectangle
⇒4× side=2(length+breadth)
⇒4×side=2(40+22)
⇒4×side=2×62
⇒ side=
4
2×62
=31cm
Thus, the side of the square is 31cm.
Now, Area of rectangle=length×breadth=40×22=880cm
2
And Area of square=side×side=31×31=961cm
2
Therefore, on comparing, the area of square is greater than that of rectangle.
How satisfied are you with the
Given :
Length and Breadth of a rectangle are 40 cm and 22 cm .
To Find :
Solution :
Length of a Rectangular Wire = 40cm
Breadth of a Rectangular Wire = 22cm
Formula Used :
2 (40 + 22)
2 (62)
124 cm
So , The Perimeter of Rectangle is 124cm .
So :
Perimeter of Square = Perimeter of Rectangle
4 × Side = 124
Side = 124/4
Side = 31 cm
So , The Side of the Square is 31 cm .
____________________________
Formula Used :
40 × 22
880 cm²
Formula Used :
31 × 31
961 cm²
So , Square encloses more area .