16. Find the area of the shaded portions in Figures 5
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16. Find the area of the shaded portions in Figures 5
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Answer:
your answer is in above pic
Step-by-step explanation:
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Verified answer
[tex]\huge{\underline{\underline{\bf Formula}}}[/tex]
[tex]\underline \green{\boxed{\bf Ar(Sector) = \dfrac{\theta}{360⁰}×πr²}}[/tex]
here,
[tex]\huge{\underline{\underline{\bf Solution}}}[/tex]
[tex]\implies \sf area = \dfrac{ \cancel{90}}{ \cancel{360}} \times \dfrac{ 22}{7} \times {14}^{2} \\ \\ \implies \sf area = \frac{1}{4} \times \frac{22}{ \cancel{7}} \times \cancel{196} \\ \\ \implies\sf area = \frac{1}{ \cancel4} \times 22 \times \cancel{28} \\ \\ \implies \sf area = 22 \times 7 = 154 [/tex]
Now, since there are two quadrants of the circle. we will multiply the gotten answer with 2
Required area = 2×154 = 308 cm²
So, the required answer is:-
[tex] \longrightarrow{\boxed{\bf 308 cm²}}[/tex]
Additional information:-
[tex]\underline \red{\boxed{\bf Ar(Sector) = \dfrac{\theta}{360⁰}×2πr}}[/tex]