16) The work done by a body on application of a constant force is the product of the constant force and the distance travelled by the body in the direction of force. Express this in the form of a linear equation in two variables and draw its graph by taking the constant force as 3 units. What is the work done when the distance travelled is 2 units. Verify it by plotting the graph.
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Your Answer:-
It is Given that
[tex]\tt y= Fx \\\\ \tt Where,\\\\ \star y =Work\ \ Done \\\\ \tt \star F = force \\\\ \tt \star x=distance/displacement\\[/tex]
Also Given ,
force = 3 units
So, y = 3x
=> y - 3x = 0
So, this is the linear equation in two variables.
So, Now next part of the Question
We have Given that x=2units
y - 2(2) = 0
=> y = 6
So, work done is 6 units
Now verifying,
By plotting the graph
Let y =0
=> 0 = 3x
=> 0 = x
So, x = 0
So, the point is A(0,0)
And
Let x = 1
=> y = 3(1)
=> y = 3
So, the point is B(1,3)
To verify the answer,
draw a perpendicular to x axis at the point (2,0) meeting the line y - 3x = 0 at any point, So the coordinates of intersection is (2,6). This shows y = 6 , so work done is 6 units
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