Calculate time in which activity of a substance is reduced to 1/16th of initial. Given that half-life is
10 days.
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Calculate time in which activity of a substance is reduced to 1/16th of initial. Given that half-life is
10 days.
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Explanation:
Let T days be the half-life period.
After one half-life period, the activity reduces to one half of its initial activity.
In 40 days, the activity reduces to 1/16
th
of its initial activity.
16
1
=(
2
1
)
4
This corresponds to four half life periods or 4T days.
4T=40
T=10
Hence, the half-life of the radioactive substance is 10 days.