Factorise each of the following: 1/9x²y² – 1/16y²z² using identites
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Factorise each of the following: 1/9x²y² – 1/16y²z² using identites
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Answer:
using identity-
[tex]{a}^{2} - {b}^{2} = (a - b)(a + b)[/tex]
1/9x²y² - 1/16 y²z²
[tex] ({\frac{1xy}{3} }^{2}) - ({ \frac{1yz}{4} }^{2}) = ( \frac{1xy}{3} - \frac{1yz}{4} )( \frac{1xy}{3} + \frac{1yz}{4} )[/tex]
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Step-by-step explanation:
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Step-by-step explanation:
(1÷9x^2y^2)-(1÷16y^2z^2)
{(1÷3xy)^2}-{(1÷4yz)^2}
(xy÷3+yz÷4)(xy÷3-yz÷4) [a^2-b^2=(a+b) (a-b) ]
(x^2y^2÷9) (y^2z^2÷16) {on multiplication}