17) Show that the points A (1, 2), B (– 1, – 16) and C (0, – 7) lie on the graph of the linear equation y = 9x – 7.
Share
17) Show that the points A (1, 2), B (– 1, – 16) and C (0, – 7) lie on the graph of the linear equation y = 9x – 7.
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Verified answer
Your Answer:
If we put the value of x in the Equation, and if we get the correct value of y, then it will be proved that the points lie on same coordinate.
In case 1,
Where the point is (1,2)
So, x = 1 and y = 2
Putting value of x in the Equation
[tex]\tt y = 9(1) - 7 \\\\ \tty = 9 -7 \\\\ \tt y = 2[/tex]
Hence this point lies on the graph of linear Equation y = 9x - 7
In Case 2,
Where the point is (-1,-16)
So, x = -1 and y = -16
Putting value of x in the Equation
[tex]\tt y = 9(-1) - 7 \\\\ \tt y = -9 -7 \\\\ \tt y = -16[/tex]
Hence this point lies on the graph of linear Equation y = 9x - 7
In Case 3,
Where the point is (0,-7)
So, x = 0 and y = -7
Putting value of x in the Equation
[tex]\tt y = 9(0) - 7 \\\\ \tt y = 0 -7 \\\\ \tt y = -7[/tex]
Hence this point lies on the graph of linear Equation y = 9x - 7
Hence all the points lie on the Graph of linear Equation y = 9x - 7
Proved
Step-by-step explanation:
7=−16
For C(0,−7), we have - 7=9(0)−7=0−7=−7
We see that the line y=9x−7 is satisfied by the points A(1,2),B(−1,−16) and C(0,−7).
Therefore, A(1,2),B(−1,−16) and C(0,−7) are solutions of the linear equation y=9x−7 and therefore, lie on the graph of the linear equation y=9x−7.