In Fig. 9, is shown a sector OAP of a circle with centre O, containing ∠ϴ. AB is perpendicular the radius OA and meets OP produced at B. Prove that the perimeter of the shaded region is r [ tan theta + sec theta + π theta/180 - 1 ]
In Fig. 9, is shown a sector OAP of a circle with centre O, containing ∠ϴ. AB is perpendicular the radius OA and meets OP produced at B. Prove that the perimeter of the shaded region is r [ tan theta + sec theta + π theta/180 - 1 ]
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Answer:
Step-by-step explanation:
[email protected]=ab/oa
Ab = [email protected]
[email protected] = ob/oa
Ob = [email protected]
Now circumference of scetor
@/360 ×2×22/7×r
[email protected] × pie× r/180
So
Perimeter of shade region
[email protected] + [email protected] + [email protected]/180 -r
=r[[email protected] + [email protected] + [email protected]/180-1]
hence proved
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Answer:
Step-by-step explanation: