Can you plz check my solution:- for Qno.4
let the first digit be "x"
also let the 2nd digit be (11-x)
therefore original no=
10(x)+1(11-x)
10x+11-x
9x+11....
therefore by interchanging the digits,we get:-
1(x)+10(11-x)
x+110-10x
110-9x
ACC TO QUESTION:-
ORIGINAL NO-NEW NO=9
9x+11-(110-9x)=9
9x+11-110+9x=9
18x-99=9
18x=9+99
18x=108
x=108/18
x=6
answer Q.no 5
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