1/(1+tan^2 theta) + 1 / (1+cot^2 theta) = 1 Prove this
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1/(1+tan^2 theta) + 1 / (1+cot^2 theta) = 1 Prove this
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Answer:
[tex] \alpha e \beta \pi \: [/tex]
for this use above formula to find the anser
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L.H.S
1/ (1+ tan^2 thetha) + 1/ (1+cot^2thetha)
1/(sec^2thetha) + 1/ (cosec^2thetha)
(cos^2 thetha) + (sin^2thetha) = 1 R.H.S
Hence L.H.S = R.H.S