- (1-sin x) / (1+sin x)=
(sec x-tan x)²
(sec x+tan x)²
(tan x-sec x)²
(tan
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- (1-sin x) / (1+sin x)=
(sec x-tan x)²
(sec x+tan x)²
(tan x-sec x)²
(tan
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HELLO DEAR,
A simpler derivation is given below :
ANSWER
1+sinx1−sinx=1+sinx1−sinx×1+sinx1+sinx=(1+sinx)21−sin2x=(1+sinx)2cos2x=(1+sinxcosx)2=(secx+tanx)2
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