find the value of ∫dx/1−sinx
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Answer:
integration of 1/1-sinx.dx
integration of 1/1-sinx*1+sinx/1+sinx.dx
integration of 1+sinx/1-sin^2x.dx
integration of 1+sinx/cos^2x.dx
integration of 1/cos^2x.dx+integration of sinx/cosx*1/cosx.dx
sec^2x+tanx.secx+c
secx(secx+tanx)+c..
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