If angles of a triangle are (x - 40), (x - 20) and ( x/2 - 10 ).Find the value of x.
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If angles of a triangle are (x - 40), (x - 20) and ( x/2 - 10 ).Find the value of x.
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The sum of angles of triangle is 180°.
So, (x-40)+(x-20)+(x/2-10)=180°
x-40+x-20+{(x-20)/2}=180
x+x+40-20+(x-20)/2=180
2x+20+(x-20)/2=180
(4x+40+x-20)/2=180
(4x+x+40-20)/2=180
(5x+20)/2=180
5x+20=180×2
5x+20=360
5x=360-20
5x=340
x=340/5
x=68°