rationalize the denominator:3/2-√2=a+b√2
Share
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
[tex]\frac{6+3\sqrt{2} }{2 }[/tex]
Step-by-step explanation:
[tex]\frac{3}{2-\sqrt{2} } =a+b\sqrt{2}[/tex]
[tex]\frac{3}{2-\sqrt{2} } *\frac{2+\sqrt{2} }{2+\sqrt{2} }[/tex]
=[tex]\frac{6+3\sqrt{2} }{2^{2}-\sqrt{2} ^{2} } }[/tex]
=[tex]\frac{6+3\sqrt{2} }{4-2 }[/tex]
=[tex]\frac{6+3\sqrt{2} }{2 }[/tex]