What is the resistance between A and B in the following circuit (Fig. 10.16)?
(a) 1 Ω
(b) 2 Ω
(c) ½ Ω
(d) 3/2 Ω
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What is the resistance between A and B in the following circuit (Fig. 10.16)?
(a) 1 Ω
(b) 2 Ω
(c) ½ Ω
(d) 3/2 Ω
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Answer:
Explanation:
To begin this question, let us start from the left. This also has a reason & quote, if nothing goes right go left!
We can see 1 ohm and 1 ohm in series. So it gets added.
1 + 1 = 2 ohm.
Now, 2 ohm and base triangle 2 ohm are in Parallel.
= 1 ohm.
We get the total triangle resistance as 1 ohm.
Again, we can see 1 ohm and 1 ohm gets added in series, so we get 2 ohm.
And again 2 ohm are in parallel.
= 1 ohm.
Again 1 ohm and 1 ohm gets added to form 2 ohm, 2 ohm again in parallel. Again total resistance is 1 ohm.
Thus in last Triangle also, we again add 1 ohm with 1 ohm and get 2 ohm. It is again in parallel with the base 2 ohm. So, we get
= 1 ohm.
So, 1 ohm is the final answer.