2. A farmer moves along the
boundary of a square field of side
10 m in 40 s. What will be the
magnitude of displacement of the
farmer at the end of 2 minutes 20
seconds from his initial position?
pls write in easy language
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2. A farmer moves along the
boundary of a square field of side
10 m in 40 s. What will be the
magnitude of displacement of the
farmer at the end of 2 minutes 20
seconds from his initial position?
pls write in easy language
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side of the square = 10m (10*4)
perimeter = 40 m
time =40sec
Thus, in the 1 sec farmer covers a distance of 1m..
so, the distance cover by the farmer in 2min 20sec = 1*140 = 140 m
The total no. of rotation the farmer makes to cover the distance of 140m =
total distance / perimeter = 140/40 = 7/2 = 3.5 m
displacement. s = √10 ^2 + 10^2
s = 10√2
s = 14.14 m ans
hope it's correct.. mark the answer brainliest