Find the compound interest to the nearest rupee
on 10,800 for 2 *1/2 at 10% per annum.
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Find the compound interest to the nearest rupee
on 10,800 for 2 *1/2 at 10% per annum.
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Answer:
amount= principle + interest
interest= amount - principle
year = 2 1/2= 5/2
amount = p(1+r/100)^n
= 10800(1+10/100)^5/2
=10800(110/100)^5/2
=10800×1.269
=13705.8
=13706 RS. (approx)
I = 13706-10800
=2906 RS.
Step-by-step explanation:
so pls check the attachment above....