If the concentration of the reactant is doubled and rate of the reaction is halved , the the order of the reaction will be ?
a) 2
b) 1
c) -1
d) 1/2
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If the concentration of the reactant is doubled and rate of the reaction is halved , the the order of the reaction will be ?
a) 2
b) 1
c) -1
d) 1/2
Dont spam .Fake people stay away
Reply correctly i will mark as brainliest .
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If the concentration of the reactant is doubled and rate of the reaction is halved , the the order of the reaction will be ?
a) 2 ✔
b) 1
c) -1
d) 1/2
Cause,The rate is proportional to the square of the concentration of a reactant is always twice (2).
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Verified answer
[tex]\color{Orange}{❥Answer}[/tex]
2
If the concentration of the reactant is doubled and rate of the reaction is halved , the the order of the reaction will be ?
(a) 2 ✓
(b) 1
(c) -1
(d) 1/2
Given:-
If the concentration of the reactant is doubled and rate of the reaction is halved , the order of the reaction will be ?
To Assume:-
The order of the reaction
Solution:-
For a 1st order reaction t ½ in independent of initial conc.
For a zero order reaction
t ½ =a2k0
In this case doubling the conc. (a) would jave doubled t ½
For a 2nd order reaction
t ½=1ka
In this case, doubling the conc. (a) would have halved the t ½ . Thus, the reaction is of 2nd order.
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