2. Find the area of circle whose perimeter is
(i) 28 cm
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2. Find the area of circle whose perimeter is
(i) 28 cm
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Answer:
A=πr2
p=2πr
Solving forA
A=p2
4π=282
4·π≈62.38874
Step-by-step explanation:
Given :-
Given :-Diameter = 28 cm.
Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.
Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²
Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²\begin{gathered}= \frac{22}{7} \times 14 \times 14 \\ = 22 \times 2 \times 14 \\ = 44 \times 14 \\ = 616 {cm}^{2}\end{gathered}
Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²\begin{gathered}= \frac{22}{7} \times 14 \times 14 \\ = 22 \times 2 \times 14 \\ = 44 \times 14 \\ = 616 {cm}^{2}\end{gathered} =
Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²\begin{gathered}= \frac{22}{7} \times 14 \times 14 \\ = 22 \times 2 \times 14 \\ = 44 \times 14 \\ = 616 {cm}^{2}\end{gathered} = 7
Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²\begin{gathered}= \frac{22}{7} \times 14 \times 14 \\ = 22 \times 2 \times 14 \\ = 44 \times 14 \\ = 616 {cm}^{2}\end{gathered} = 722
Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²\begin{gathered}= \frac{22}{7} \times 14 \times 14 \\ = 22 \times 2 \times 14 \\ = 44 \times 14 \\ = 616 {cm}^{2}\end{gathered} = 722
Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²\begin{gathered}= \frac{22}{7} \times 14 \times 14 \\ = 22 \times 2 \times 14 \\ = 44 \times 14 \\ = 616 {cm}^{2}\end{gathered} = 722 ×14×14
Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²\begin{gathered}= \frac{22}{7} \times 14 \times 14 \\ = 22 \times 2 \times 14 \\ = 44 \times 14 \\ = 616 {cm}^{2}\end{gathered} = 722 ×14×14=22×2×14
Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²\begin{gathered}= \frac{22}{7} \times 14 \times 14 \\ = 22 \times 2 \times 14 \\ = 44 \times 14 \\ = 616 {cm}^{2}\end{gathered} = 722 ×14×14=22×2×14=44×14
Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²\begin{gathered}= \frac{22}{7} \times 14 \times 14 \\ = 22 \times 2 \times 14 \\ = 44 \times 14 \\ = 616 {cm}^{2}\end{gathered} = 722 ×14×14=22×2×14=44×14=616cm
Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²\begin{gathered}= \frac{22}{7} \times 14 \times 14 \\ = 22 \times 2 \times 14 \\ = 44 \times 14 \\ = 616 {cm}^{2}\end{gathered} = 722 ×14×14=22×2×14=44×14=616cm 2
Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²\begin{gathered}= \frac{22}{7} \times 14 \times 14 \\ = 22 \times 2 \times 14 \\ = 44 \times 14 \\ = 616 {cm}^{2}\end{gathered} = 722 ×14×14=22×2×14=44×14=616cm 2
Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²\begin{gathered}= \frac{22}{7} \times 14 \times 14 \\ = 22 \times 2 \times 14 \\ = 44 \times 14 \\ = 616 {cm}^{2}\end{gathered} = 722 ×14×14=22×2×14=44×14=616cm 2
Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²\begin{gathered}= \frac{22}{7} \times 14 \times 14 \\ = 22 \times 2 \times 14 \\ = 44 \times 14 \\ = 616 {cm}^{2}\end{gathered} = 722 ×14×14=22×2×14=44×14=616cm 2
Given :-Diameter = 28 cm.Radius = D/2 = 14 cm.Area of circle = πr²\begin{gathered}= \frac{22}{7} \times 14 \times 14 \\ = 22 \times 2 \times 14 \\ = 44 \times 14 \\ = 616 {cm}^{2}\end{gathered} = 722 ×14×14=22×2×14=44×14=616cm 2 Hence the area of the given circle is 616 cm².