2) The area of a right angled triangle is 27sqom and longer side
(perpendicular) is 3cm more that the base Find the hypotenuse
hey mates please help
correct one will be marked as branliest
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2) The area of a right angled triangle is 27sqom and longer side
(perpendicular) is 3cm more that the base Find the hypotenuse
hey mates please help
correct one will be marked as branliest
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Step-by-step explanation:
As perpendicular is 3 more than base
so let base be x then perpendicular will be x+3
as by area of right angle triangle
27=1/2 * x*x+3
27=(x sq +3)/2
27*2=x sq +3
54=x sq +3
hope it will help you :)
mark it as brainliest
Answer:
GIVEN- AREA=27 SQCM
PERPENDICULAR IS 3CM
LET THE BASE BE-X CM
3+X CM
Step-by-step explanation:
AREA OF RIGHT TRIANGLE-HALF * BASE *HEIGHT
A/Q
27=half *(3+x)*3
54= 9+3x
54-9=3x
5=3x
x=5/3
it may help you!!!