A body is projected vertical ly upward with a velocity of 10 m/s.it reaches maximum height h at time t. in time t/2 , the height covered is??
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A body is projected vertical ly upward with a velocity of 10 m/s.it reaches maximum height h at time t. in time t/2 , the height covered is??
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Answer:
5m is the correct ans
Explanation:
Taking g=10m/s^2
therefore,applying the eqn of motio
v^2=u^2-2gh
at max ht v=0
and u = 10m/s
thus, (0)^2=(10)^2-2(10)(h)
h=100/20 =>5m :) mark as brainliest if found helpful