2 years ago, my age was 4 1/2 times the age of my son then. 6 years ago, my age was twice the square of my son then. find the present age of my son
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2 years ago, my age was 4 1/2 times the age of my son then. 6 years ago, my age was twice the square of my son then. find the present age of my son
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Answer:
Let 6 years back from now my son was m years old , so then i was 2m^2 years old . Four years after then , i was (2m^2+4) years and my son was (m+4) years .
(m+4)×4.5 = 2m^2+4
or, 9m+36=4m^2+8
or 4m^2–9m-28=0
or, 4m^2–16m+7m-28=0
or, 4m(m-4)+7(m-4)=0
or, (m-4)(4m+7) =0
or m = 4 or, -7/4
-ve age omitted
So 6 years back from now age of my son was 4 years , so now my son's age is 4+6=10 years , ans