If x^2 + bx + b + 3 = 0 has roots of the form (-b +- √5)/2, where b > 0, then b = m+√n for positive integers m,n. Find m + n.
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2, where b > 0, then b = m+√n for positive integers m,n. Find m + n
If x^2 + bx + b + 3 = 0 has roots of the form (-b +- √5)/2, where b > 0, then b = m+√n for positive integers m,n. Find m + n.
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Answer:
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