20ml of 0.4M H2SO4 and 80ml of 0.2M NaOH are mixed. then the PH of the resulting solution is
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20ml of 0.4M H2SO4 and 80ml of 0.2M NaOH are mixed. then the PH of the resulting solution is
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Answer
pH = 7
Number of moles = Molarity X Volume
Moles of H2SO4 = 0.02 X 0.4 = 0.008 moles
Moles of NaOH = 0.08 X 0.2 = 0.016 moles
2 moles of NaOH are required to neutralize 1 mole of H2SO4 as 2 moles of H+ ions are generated.
Therefore 0.008 moles of H2SO4 are neutralized by 0.016
Moles of NaOH. Hence the pH of solution will be 7.
Answer:
2 moles of NaOH are required to neutralize 1 mole of H2SO4 as 2 moles of H+ ions are generated. Moles of NaOH. Hence the pH of solution will be 7.
Explanation:
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