22. Find the area of a quadrilateral piece of ground
one of whose diagonals is 60 metres long and the
perpendiculars from the other two vertices are 38
and 22 metres respectively.
tions
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22. Find the area of a quadrilateral piece of ground
one of whose diagonals is 60 metres long and the
perpendiculars from the other two vertices are 38
and 22 metres respectively.
tions
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Answer:
We know that the area of a quadrilateral is equal to the product of one diagonal and half the sum of perpendiculars drawn on it from other two vertices.
⇒ Area of a quadrilateral =
2
1
×diagonal×(p
1
+p
2
)
where, p
1
and p
2
are two perpendiculars drawn from opposite vertices$$
Given, length of one diagonal is 60m and the perpendiculars from the other two vertices are 38m and 22m, respectively.
⟹ Area of the quadrilateral =
2
1
×60×(38+22)m
2
=1800m
2