26) The average of 50 numbers is 32. If two numbers 22 and 18 are discarded, then find the average of remainit numbers?
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26) The average of 50 numbers is 32. If two numbers 22 and 18 are discarded, then find the average of remainit numbers?
Please sand only full formula...
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Step-by-step explanation:
The average of the remaining numbers will be 37.5.
Solution:
The average of 50 numbers is 38
We know that,
\text { Average } = \frac { \text { Sum of the observations } } { \text { Total number of Observations} } Average =
Total number of Observations
Sum of the observations
Here, total = 50 and average = 38
The sum of all the 50 numbers are = 50×38 = 1900
The Sum of the given two numbers = 45+55 = 100
After discarding two numbers, total numbers left now are = 48
The total sum of the remaining 48 numbers are = 1900-100 = 1800
∴ The remaining average of the 48 numbers are
= \frac {1800}{48} = 37.5=
48
1800
=37.5
Thus, the average of the remaining numbers will be 37.5.
refer to attachment
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Step-by-step explanation:
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