27. A bag contains 3 red balls, 2 blue balls and 4 yellow balls. If R, B and Y are elementary events, then prove that P(R) + P(B) + P(Y) = 1.
NO SPAM PLEASE THIS IS MY EXAM RELATED QUESTION !!
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27. A bag contains 3 red balls, 2 blue balls and 4 yellow balls. If R, B and Y are elementary events, then prove that P(R) + P(B) + P(Y) = 1.
NO SPAM PLEASE THIS IS MY EXAM RELATED QUESTION !!
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Step-by-step explanation:
P(R)=3/9
P(B)=2/9
P(Y)=4/9
P(R)+P(B)+P(Y)=3/9+2/9+4/9=9/9=1
Verified answer
number of red balls=3
number of blue balls=2
number of yellow balls=4
total number of balls=9
probability of red balls p(R)=3/9=1/3
probability of blue balls p(B)=2/9
probability of yellow balls p(y)=4/9
p(R)+p(B)+p(y)=1
1/3+2/9+4/9
3+2+4/9
9/9
1