27. The 4th term of an AP is zero. Prove that its 25th term is triple its 11th term.
(CBSE 2005)
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27. The 4th term of an AP is zero. Prove that its 25th term is triple its 11th term.
(CBSE 2005)
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Answer:
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Step-by-step explanation:
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SOLUTION :-
Given that,
4th term = 0
Let first term be a and common difference be d.
We know that,
We have to prove that,
25th term = 3 × 11th term
∴ L.H.S = R.H.S
Hence proved.