In Fig.6.38, the sides AB and AC of ∆ABC are produced to point E and Don't respectively.If bisectors BO and CO of angle CBE and angle BCD respectively meet at point O,then prove that angleBOC = 90°-1/2angle BAC.
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In Fig.6.38, the sides AB and AC of ∆ABC are produced to point E and Don't respectively.If bisectors BO and CO of angle CBE and angle BCD respectively meet at point O,then prove that angleBOC = 90°-1/2angle BAC.
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