established equation is equal to UT+1/2AT^2 by graphical method
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s= ut+(1/2) at^2
let me help with a figure
oh by the way, this equation only holds for uniform motion! (constant acceleration)
Now here I assume you know some things about graph of V and T under constant acceleration.
1) That slope (steepness, how much it rises) is equal to a.
2) initial speed is u.
3) after time t, speed is v.
4)area under this graph is distance (comment if you want to know explaination of this)
5) area of rectangle and triangle formulas are used.
Hope it helps.