[sin(n+1)a -sin(n-1)a] /
[cos(n+1a + 2 cos na + cos(n-1)a ]
a) Tan(a/2)
b) cot(a/2)
c) cota
d) tan a
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Answer:
answer of sin(n+1)a -sin(n-1)a] /
[cos(n+1a + 2 cos na + cos(n-1)a ]
a) Tan(a/2)
b) cot(a/2)
c) cota
d) tan a
Step-by-step explanation:
d