2cos^2theta +3sintheta=3, theta=?
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see.....
above written value is equal to zero only and only when 2 cos ² Φ = zero and sinΦ = 1
we know ,
2 cos²Φ = 0
cos²Φ = 0
cos Φ = 0
but,
cos 90° = 0
so theeta is 90° in this case
if we consider sin case then
sin Φ = 1
but,
sin90° = 1
so theeta = 90°
so theeta here is again 90°....
so in both cases theeta is 90°.... hence theeta is 90°