For a satellite moving in an orbit around the
earth, the ratio of kinetic energy to potential
energy is
a) 2
b) 1/2
c) 1/√2
d) √2
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For a satellite moving in an orbit around the
earth, the ratio of kinetic energy to potential
energy is
a) 2
b) 1/2
c) 1/√2
d) √2
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Explanation:
We know that,
Potential energy,
U=−
R
e
GM
e
m
Where,
M
e
=Mass of the earth
m=Mass of satellite
R
e
= Radius of the earth
G= Gravitational constant
Now,
∣U∣=
R
e
GM
e
m
Now, kinetic energy
K=
2
1
R
e
GM
e
m
Now,
∣U∣
K
=
2
1
R
e
GM
e
m
×
GM
e
m
R
e
∣U∣
K
=
2
1
Hence, the ratio of kinetic energy to potential energy is
2
1