2sin²B - cos²B = 2 , the B = ?
please provide complete answer step wise
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2sin²B - cos²B = 2 , the B = ?
please provide complete answer step wise
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Answer:
[Taking RHS:
cos(A−B)[cos(A−B)−2cosA.cosB]+cos2B
=cos(A−B)[cosA.cosB+sinA.sinB−2cosA.cosB]+cos2B
=−cos(A−B).cos(A+B)+cos2B
=cos2B−22cos(A−B)cos(A+B)
=21[2cos2B−cos2A−cos2B]
=21[2sin2A]=sin2A[/tex]
Step-by-step explanation:
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