2x² + 5root3x + 6 solve this by using qudratic formula
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Verified answer
Step-by-step explanation:
Given -
To Find -
As we know that :-
⇝2x² + 5√3x + 6
here,
a = 2
b = 5√3
c = 6
Now,
⇝-(5√3) ± √(5√3)² - 4× (2) × (6)/2(2)
⇝-5√3 ± √75 - 48/4
⇝-5√3 ± √27/4
⇝-5√3 ± 3√3/4
Zeroes are -
x = -5√3 + 3√3/4
⇝-2√3/4
⇝-√3/2
And
x = -5√3 - 3√3/4
⇝-8√3/4
⇝-2√3
Hence,
Zeroes of the given polynomial are -√3/2 and -2√3
Verification :-
⇝-√3/2 + -2√3 = -5√3/2
⇝-√3 - 4√3/2 = -5√3/2
⇝-5√3/2 = -5√3/2
LHS = RHS
And
⇝-√3/2 × -2√3 = 6/2
⇝3 = 3
LHS = RHS
Hence,
Verified...
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