(2x-y+z)^2 expand the sum using suitable identites
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Answer:
4x^2+y^2+z^2-4xy-2yz+4xz
Step-by-step explanation:
(2x-y+z)^2
using the identity => (a-b+c)^2
= a^2+b^2+c^2-2ab-2bc+2ca
=> (2x)^2 + (y)^2+(z)^2-2×2x×y-2×y×z+2×z×2x
=> 4x^2+ y^2+z^2-4xy-2yz+4xz
hope you understand...
Answer:
4x^2+y^2+z^2-4xy-2yz+4xz
Step-by-step explanation:
Its in the form of
(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca
(2x-y+z)^2=(2x)^2+(-y)^2+(z)^2+2(2x)(-y)+2(-y)(z)+2(z)(2x)
(2x-y+z)^2=4x^2+y^2+z^2-2xy-2yz+4xz