3^x+3 + 3^x+4/3 = 162
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[tex]3 {}^{x} + 3 + 3 {}^{x} + \frac{4}{3} = 162 \\ 3 {}^{2x} + 3 + \frac{4}{3} = 162 \\ \frac{3 {}^{2x}3 + 9 + 4 }{3} = 162 \\ 3 {}^{2x + 1} + 13 = 162 \times 3 \\ 3 {}^{2x + 1} = 486 - 13 \\ 3 {}^{2x + 1} = 473 \\ [/tex]
Answer:
answer is 473
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